Problem 16.20


(a) Write an equation for the reaction in which H2C6H5O7- acts as a base in H2O(l).

If H2C6H5O7- is a base, then it accepts a proton from water; hence,

H2C6H5O7-(aq) + H2O(l) = H3C6H5O7 + OH-(aq)

Pay attention to the charges when you protonate the base to form the conjugate acid!

(b) Write an equation for the reaction in which H2C6H5O7- acts as an acid in H2O(l)

If H2C6H5O7- acts as an acid, then it donates a proton to water.....

H2C6H5O7-(aq) + H2O(l) = HC6H5O7-2 + H3O+(aq)

(c) What is the conjugate acid of H2C6H5O7-? What is its conjugate base?

The conjugate acid of H2C6H5O7- is H3C6H5O7 (add a proton); the conjugate base of H2C6H5O7- is HC6H5O7-2 (remove a proton.)


If you have any questions or comments, reply to chapman@sou.edu
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Doug Chapman chapman@sou.edu 5/25/15