(a) Write an equation for the reaction in which H2C6H5O7- acts as a base in H2O(l).
If H2C6H5O7- is a base, then it accepts a proton from water; hence,
H2C6H5O7-(aq) + H2O(l) = H3C6H5O7 + OH-(aq)
Pay attention to the charges when you protonate the base to form the conjugate acid!
(b) Write an equation for the reaction in which H2C6H5O7- acts as an acid in H2O(l)
If H2C6H5O7- acts as an acid, then it donates a proton to water.....
H2C6H5O7-(aq) + H2O(l) = HC6H5O7-2 + H3O+(aq)
(c) What is the conjugate acid of H2C6H5O7-? What is its conjugate base?
The conjugate acid of H2C6H5O7- is H3C6H5O7 (add a proton); the conjugate base of H2C6H5O7- is HC6H5O7-2 (remove a proton.)
Doug Chapman email@example.com 5/25/15